Android Kotlin Fragmentadapter
刚接触kotlin写安卓, 一脸懵逼, 连教程都没看就开搞了
直接上代码
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package ${package}.base
import androidx.fragment.app.Fragment
import androidx.fragment.app.FragmentManager
import androidx.fragment.app.FragmentPagerAdapter
/**
* Fragment适配器, ViewPager用
* @property fm FragmentManager
* @property fragments MutableList<Fragment>
* @property fragmentTitles MutableList<String>
* @constructor
*/
class QJFragmentAdapter(val fm: FragmentManager) : FragmentPagerAdapter(fm,BEHAVIOR_RESUME_ONLY_CURRENT_FRAGMENT) {
var fragments: MutableList<Fragment> = ArrayList()
var fragmentTitles: MutableList<String> = ArrayList()
override fun getItem(position: Int): Fragment {
return fragments[position]
}
fun addFragment(fragment: Fragment, title: String) {
fragments.add(fragment)
fragmentTitles.add(title)
}
override fun getPageTitle(position: Int): CharSequence? {
return fragmentTitles[position]
}
override fun getCount(): Int = fragments.size
}
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使用方式很简单
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var adapter = QJFragmentAdapter(supportFragmentManager)
var makeLeaveFragment = MakeLeaveFragment()
var leaveListFragment = LeaveListFragment()
adapter.addFragment(MakeLeaveFragment(), makeLeaveFragment.title)
adapter.addFragment(LeaveListFragment(), leaveListFragment.title)
viewPager.adapter = adapter
tabLayout.setupWithViewPager(viewPager)
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可以简化的地方: 创建一个BaseFragment, 声明一个title的属性, 然后每个Fragment类都继承这个, 就可以改成 adapter.addFragment(MakeLeaveFragment())
这样少一行代码了